1 // Copyright 2008-2009 Wincent Colaiuta. All rights reserved.
3 // Redistribution and use in source and binary forms, with or without
4 // modification, are permitted provided that the following conditions are met:
6 // 1. Redistributions of source code must retain the above copyright notice,
7 // this list of conditions and the following disclaimer.
8 // 2. Redistributions in binary form must reproduce the above copyright notice,
9 // this list of conditions and the following disclaimer in the documentation
10 // and/or other materials provided with the distribution.
12 // THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS"
13 // AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
14 // IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
15 // ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT HOLDERS OR CONTRIBUTORS BE
16 // LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR
17 // CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF
18 // SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS
19 // INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN
20 // CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE)
21 // ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE
22 // POSSIBILITY OF SUCH DAMAGE.
28 ary_t *ary = ALLOC_N(ary_t, 1);
30 ary->max = DEFAULT_ENTRY_COUNT;
31 ary->entries = ALLOC_N(int, DEFAULT_ENTRY_COUNT);
35 int ary_entry(ary_t *ary, int idx)
38 idx = ary->count + idx;
39 return (idx >= 0 && ary->count > idx) ? ary->entries[idx] : INT_MAX;
42 void ary_clear(ary_t *ary)
47 int ary_pop(ary_t *ary)
57 void ary_push(ary_t *ary, int val)
59 if (ary->count == ary->max)
61 ary->max += DEFAULT_ENTRY_COUNT;
62 REALLOC_N(ary->entries, int, ary->max);
64 ary->entries[ary->count] = val;
68 int ary_includes(ary_t *ary, int val)
70 for (int i = 0, max = ary->count; i < max; i++)
72 if (ary->entries[i] == val)
78 int ary_count(ary_t *ary, int item)
81 for (int i = 0, max = ary->count; i < max; i++)
83 if (ary->entries[i] == item)
89 void ary_free(ary_t *ary)